132131247431 has 2 divisors, whose sum is σ = 132131247432. Its totient is φ = 132131247430.

The previous prime is 132131247379. The next prime is 132131247433. The reversal of 132131247431 is 134742131231.

It is a strong prime.

It is an emirp because it is prime and its reverse (134742131231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132131247431 - 2¹⁴ = 132131231047 is a prime.

It is a super-2 number, since 2×132131247431² (a number of 23 digits) contains 22 as substring.

Together with 132131247433, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132131247433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66065623715 + 66065623716.

It is an arithmetic number, because the mean of its divisors is an integer number (66065623716).

Almost surely, 2^132131247431 is an apocalyptic number.

132131247431 is a deficient number, since it is larger than the sum of its proper divisors (1).

132131247431 is an equidigital number, since it uses as much as digits as its factorization.

132131247431 is an evil number, because the sum of its binary digits is even.

The product of its digits is 12096, while the sum is 32.

Adding to 132131247431 its reverse (134742131231), we get a palindrome (266873378662).

The spelling of 132131247431 in words is "one hundred thirty-two billion, one hundred thirty-one million, two hundred forty-seven thousand, four hundred thirty-one".