12103041479 has 2 divisors, whose sum is σ = 12103041480. Its totient is φ = 12103041478.

The previous prime is 12103041463. The next prime is 12103041481. The reversal of 12103041479 is 97414030121.

12103041479 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (97414030121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12103041479 - 2⁴ = 12103041463 is a prime.

It is a super-2 number, since 2×12103041479² (a number of 21 digits) contains 22 as substring.

Together with 12103041481, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12103041179) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6051520739 + 6051520740.

It is an arithmetic number, because the mean of its divisors is an integer number (6051520740).

Almost surely, 2^12103041479 is an apocalyptic number.

12103041479 is a deficient number, since it is larger than the sum of its proper divisors (1).

12103041479 is an equidigital number, since it uses as much as digits as its factorization.

12103041479 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 32.

The spelling of 12103041479 in words is "twelve billion, one hundred three million, forty-one thousand, four hundred seventy-nine".