Base | Representation |
---|---|
bin | 10001100111001100010… |
… | …001101111001111111100 |
3 | 11021201000210110102011000 |
4 | 101213030101233033330 |
5 | 124312210112342340 |
6 | 2324002104130300 |
7 | 153304453601034 |
oct | 21471421571774 |
9 | 4251023412130 |
10 | 1210313012220 |
11 | 427322162894 |
12 | 176697466990 |
13 | 8a1940aa8c0 |
14 | 4281808a8c4 |
15 | 2173a2c7d30 |
hex | 119cc46f3fc |
1210313012220 has 96 divisors (see below), whose sum is σ = 4055065842240. Its totient is φ = 297923201280.
The previous prime is 1210313012189. The next prime is 1210313012221. The reversal of 1210313012220 is 222103130121.
1210313012220 is a `hidden beast` number, since 1 + 210 + 313 + 0 + 122 + 20 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 1210313012193 and 1210313012202.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1210313012221) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 86197611 + ... + 86211650.
It is an arithmetic number, because the mean of its divisors is an integer number (42240269190).
Almost surely, 21210313012220 is an apocalyptic number.
1210313012220 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1210313012220 is an abundant number, since it is smaller than the sum of its proper divisors (2844752830020).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1210313012220 is a wasteful number, since it uses less digits than its factorization.
1210313012220 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 172409292 (or 172409284 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 1210313012220 its reverse (222103130121), we get a palindrome (1432416142341).
The spelling of 1210313012220 in words is "one trillion, two hundred ten billion, three hundred thirteen million, twelve thousand, two hundred twenty".
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