Search a number
-
+
121032213300007 is a prime number
BaseRepresentation
bin11011100001010000000010…
…000101001000001100100111
3120212112120022001012122121221
4123201100002011020030213
5111330442433101100012
61105225233050121211
734331201034363562
oct3341200205101447
9525476261178557
10121032213300007
1135623523117199
12116a8a2b420207
13526c39a497879
1421c5dc18614d9
15ded4d3e8d507
hex6e1402148327

121032213300007 has 2 divisors, whose sum is σ = 121032213300008. Its totient is φ = 121032213300006.

The previous prime is 121032213299953. The next prime is 121032213300113. The reversal of 121032213300007 is 700003312230121.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 121032213300007 - 211 = 121032213297959 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121032213307007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60516106650003 + 60516106650004.

It is an arithmetic number, because the mean of its divisors is an integer number (60516106650004).

Almost surely, 2121032213300007 is an apocalyptic number.

121032213300007 is a deficient number, since it is larger than the sum of its proper divisors (1).

121032213300007 is an equidigital number, since it uses as much as digits as its factorization.

121032213300007 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512, while the sum is 25.

Adding to 121032213300007 its reverse (700003312230121), we get a palindrome (821035525530128).

The spelling of 121032213300007 in words is "one hundred twenty-one trillion, thirty-two billion, two hundred thirteen million, three hundred thousand, seven".