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12110243153040 = 2432536313463189
BaseRepresentation
bin1011000000111010001010…
…1111011100010010010000
31120212201122200000112102200
42300032202233130102100
53041403234221344130
641431211403243200
72356636054236654
oct260164257342220
946781580015380
1012110243153040
113949a1a60143a
121437067b19500
1369acb63a2816
142dc1d31b8a64
15160036548760
hexb03a2bdc490

12110243153040 has 120 divisors (see below), whose sum is σ = 40671441053880. Its totient is φ = 3229302269952.

The previous prime is 12110243152993. The next prime is 12110243153053. The reversal of 12110243153040 is 4035134201121.

12110243153040 is a `hidden beast` number, since 1 + 2 + 110 + 243 + 1 + 5 + 304 + 0 = 666.

It can be written as a sum of positive squares in 4 ways, for example, as 198716242176 + 11911526910864 = 445776^2 + 3451308^2 .

It is a tau number, because it is divible by the number of its divisors (120).

It is a super-2 number, since 2×121102431530402 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12110243152995 and 12110243153013.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 25913766 + ... + 26376954.

It is an arithmetic number, because the mean of its divisors is an integer number (338928675449).

Almost surely, 212110243153040 is an apocalyptic number.

12110243153040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

12110243153040 is an abundant number, since it is smaller than the sum of its proper divisors (28561197900840).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12110243153040 is a wasteful number, since it uses less digits than its factorization.

12110243153040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 499521 (or 499512 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 27.

Adding to 12110243153040 its reverse (4035134201121), we get a palindrome (16145377354161).

The spelling of 12110243153040 in words is "twelve trillion, one hundred ten billion, two hundred forty-three million, one hundred fifty-three thousand, forty".

Divisors: 1 2 3 4 5 6 8 9 10 12 15 16 18 20 24 30 36 40 45 48 60 72 80 90 120 144 180 240 360 720 36313 72626 108939 145252 181565 217878 290504 326817 363130 435756 463189 544695 581008 653634 726260 871512 926378 1089390 1307268 1389567 1452520 1634085 1743024 1852756 2178780 2315945 2614536 2779134 2905040 3268170 3705512 4168701 4357560 4631890 5229072 5558268 6536340 6947835 7411024 8337402 8715120 9263780 11116536 13072680 13895670 16674804 18527560 20843505 22233072 26145360 27791340 33349608 37055120 41687010 55582680 66699216 83374020 111165360 166748040 333496080 16819782157 33639564314 50459346471 67279128628 84098910785 100918692942 134558257256 151378039413 168197821570 201837385884 252296732355 269116514512 302756078826 336395643140 403674771768 504593464710 605512157652 672791286280 756890197065 807349543536 1009186929420 1211024315304 1345582572560 1513780394130 2018373858840 2422048630608 3027560788260 4036747717680 6055121576520 12110243153040