12111003413 has 2 divisors, whose sum is σ = 12111003414. Its totient is φ = 12111003412.

The previous prime is 12111003391. The next prime is 12111003431. The reversal of 12111003413 is 31430011121.

Together with next prime (12111003431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11893647364 + 217356049 = 109058^2 + 14743^2 .

It is an emirp because it is prime and its reverse (31430011121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12111003413 - 2¹² = 12110999317 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12111003391 and 12111003400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12111003433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055501706 + 6055501707.

It is an arithmetic number, because the mean of its divisors is an integer number (6055501707).

Almost surely, 2^12111003413 is an apocalyptic number.

It is an amenable number.

12111003413 is a deficient number, since it is larger than the sum of its proper divisors (1).

12111003413 is an equidigital number, since it uses as much as digits as its factorization.

12111003413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 12111003413 its reverse (31430011121), we get a palindrome (43541014534).

The spelling of 12111003413 in words is "twelve billion, one hundred eleven million, three thousand, four hundred thirteen".