12111223303132 has 24 divisors (see below), whose sum is σ = 22349220333440. Its totient is φ = 5726848126320.

The previous prime is 12111223303103. The next prime is 12111223303183. The reversal of 12111223303132 is 23130332211121.

It is a super-4 number, since 4×12111223303132⁴ (a number of 53 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 12111223303097 and 12111223303106.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 139499688 + ... + 139586479.

Almost surely, 2^{12111223303132} is an apocalyptic number.

It is an amenable number.

12111223303132 is a deficient number, since it is larger than the sum of its proper divisors (10237997030308).

12111223303132 is a wasteful number, since it uses less digits than its factorization.

12111223303132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 279086761 (or 279086759 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 12111223303132 its reverse (23130332211121), we get a palindrome (35241555514253).

The spelling of 12111223303132 in words is "twelve trillion, one hundred eleven billion, two hundred twenty-three million, three hundred three thousand, one hundred thirty-two".