Base | Representation |
---|---|
bin | 10110100011110001… |
… | …11111100011010110 |
3 | 1011021001120110020020 |
4 | 23101320333203112 |
5 | 144300444004420 |
6 | 5321443250010 |
7 | 606062314521 |
oct | 132170774326 |
9 | 34231513206 |
10 | 12111313110 |
11 | 515557a886 |
12 | 2420079906 |
13 | 11b0239780 |
14 | 82c715bb8 |
15 | 4ad40c340 |
hex | 2d1e3f8d6 |
12111313110 has 32 divisors (see below), whose sum is σ = 31303087200. Its totient is φ = 2981246208.
The previous prime is 12111313103. The next prime is 12111313129. The reversal of 12111313110 is 1131311121.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 12111313110.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15526935 + ... + 15527714.
It is an arithmetic number, because the mean of its divisors is an integer number (978221475).
Almost surely, 212111313110 is an apocalyptic number.
12111313110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12111313110 is an abundant number, since it is smaller than the sum of its proper divisors (19191774090).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12111313110 is a wasteful number, since it uses less digits than its factorization.
12111313110 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31054672.
The product of its (nonzero) digits is 18, while the sum is 15.
Adding to 12111313110 its reverse (1131311121), we get a palindrome (13242624231).
It can be divided in two parts, 12111 and 313110, that added together give a triangular number (325221 = T806).
The spelling of 12111313110 in words is "twelve billion, one hundred eleven million, three hundred thirteen thousand, one hundred ten".
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