Search a number
-
+
121116150581 is a prime number
BaseRepresentation
bin111000011001100010…
…1011100101100110101
3102120121210101221020212
41300303011130230311
53441021213304311
6131350123235205
711515241202506
oct1606305345465
9376553357225
10121116150581
1147401a00618
121b581678b05
13b5625012ba
145c0d68abad
15323ce7bc8b
hex1c3315cb35

121116150581 has 2 divisors, whose sum is σ = 121116150582. Its totient is φ = 121116150580.

The previous prime is 121116150517. The next prime is 121116150583. The reversal of 121116150581 is 185051611121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 60579976900 + 60536173681 = 246130^2 + 246041^2 .

It is a cyclic number.

It is not a de Polignac number, because 121116150581 - 26 = 121116150517 is a prime.

It is a super-2 number, since 2×1211161505812 (a number of 23 digits) contains 22 as substring.

Together with 121116150583, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121116150583) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60558075290 + 60558075291.

It is an arithmetic number, because the mean of its divisors is an integer number (60558075291).

Almost surely, 2121116150581 is an apocalyptic number.

It is an amenable number.

121116150581 is a deficient number, since it is larger than the sum of its proper divisors (1).

121116150581 is an equidigital number, since it uses as much as digits as its factorization.

121116150581 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2400, while the sum is 32.

The spelling of 121116150581 in words is "one hundred twenty-one billion, one hundred sixteen million, one hundred fifty thousand, five hundred eighty-one".