1211303143100 has 144 divisors (see below), whose sum is σ = 2844766673280. Its totient is φ = 446690764800.

The previous prime is 1211303143067. The next prime is 1211303143103. The reversal of 1211303143100 is 13413031121.

It is a super-2 number, since 2×1211303143100² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1211303143103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5479922 + ... + 5696678.

It is an arithmetic number, because the mean of its divisors is an integer number (19755324120).

Almost surely, 2^{1211303143100} is an apocalyptic number.

1211303143100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1211303143100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1422383336640).

1211303143100 is an abundant number, since it is smaller than the sum of its proper divisors (1633463530180).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1211303143100 is a wasteful number, since it uses less digits than its factorization.

1211303143100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 216888 (or 216881 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 1211303143100 its reverse (13413031121), we get a palindrome (1224716174221).

The spelling of 1211303143100 in words is "one trillion, two hundred eleven billion, three hundred three million, one hundred forty-three thousand, one hundred".