Base | Representation |
---|---|
bin | 1011000001000110101110… |
… | …0111110101000001100111 |
3 | 1120220001100112200200102222 |
4 | 2300101223213311001213 |
5 | 3041432140011041024 |
6 | 41432530035022555 |
7 | 2360115426542444 |
oct | 260215347650147 |
9 | 46801315620388 |
10 | 12113613377639 |
11 | 3950399a50024 |
12 | 143784873aa5b |
13 | 69b4026a1967 |
14 | 2dc432a349cb |
15 | 16018236d85e |
hex | b046b9f5067 |
12113613377639 has 2 divisors, whose sum is σ = 12113613377640. Its totient is φ = 12113613377638.
The previous prime is 12113613377623. The next prime is 12113613377641. The reversal of 12113613377639 is 93677331631121.
12113613377639 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12113613377639 - 24 = 12113613377623 is a prime.
Together with 12113613377641, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12113643377639) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056806688819 + 6056806688820.
It is an arithmetic number, because the mean of its divisors is an integer number (6056806688820).
Almost surely, 212113613377639 is an apocalyptic number.
12113613377639 is a deficient number, since it is larger than the sum of its proper divisors (1).
12113613377639 is an equidigital number, since it uses as much as digits as its factorization.
12113613377639 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2571912, while the sum is 53.
The spelling of 12113613377639 in words is "twelve trillion, one hundred thirteen billion, six hundred thirteen million, three hundred seventy-seven thousand, six hundred thirty-nine".
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