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12113613377639 is a prime number
BaseRepresentation
bin1011000001000110101110…
…0111110101000001100111
31120220001100112200200102222
42300101223213311001213
53041432140011041024
641432530035022555
72360115426542444
oct260215347650147
946801315620388
1012113613377639
113950399a50024
12143784873aa5b
1369b4026a1967
142dc432a349cb
1516018236d85e
hexb046b9f5067

12113613377639 has 2 divisors, whose sum is σ = 12113613377640. Its totient is φ = 12113613377638.

The previous prime is 12113613377623. The next prime is 12113613377641. The reversal of 12113613377639 is 93677331631121.

12113613377639 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12113613377639 - 24 = 12113613377623 is a prime.

Together with 12113613377641, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12113643377639) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056806688819 + 6056806688820.

It is an arithmetic number, because the mean of its divisors is an integer number (6056806688820).

Almost surely, 212113613377639 is an apocalyptic number.

12113613377639 is a deficient number, since it is larger than the sum of its proper divisors (1).

12113613377639 is an equidigital number, since it uses as much as digits as its factorization.

12113613377639 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2571912, while the sum is 53.

The spelling of 12113613377639 in words is "twelve trillion, one hundred thirteen billion, six hundred thirteen million, three hundred seventy-seven thousand, six hundred thirty-nine".