Base | Representation |
---|---|
bin | 10110100100000110… |
… | …11001100100001100 |
3 | 1011021020201001022220 |
4 | 23102003121210030 |
5 | 144302143303400 |
6 | 5322021535340 |
7 | 606124436040 |
oct | 132203314414 |
9 | 34236631286 |
10 | 12114041100 |
11 | 5157073417 |
12 | 2420b74550 |
13 | 11b0983375 |
14 | 82cc26020 |
15 | 4ad79a7a0 |
hex | 2d20d990c |
12114041100 has 72 divisors (see below), whose sum is σ = 40057102848. Its totient is φ = 2768923200.
The previous prime is 12114041081. The next prime is 12114041113. The reversal of 12114041100 is 114041121.
It is a super-3 number, since 3×121140411003 (a number of 31 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 12114041100.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2882196 + ... + 2886395.
Almost surely, 212114041100 is an apocalyptic number.
12114041100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12114041100 is an abundant number, since it is smaller than the sum of its proper divisors (27943061748).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12114041100 is a wasteful number, since it uses less digits than its factorization.
12114041100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5768615 (or 5768608 counting only the distinct ones).
The product of its (nonzero) digits is 32, while the sum is 15.
Adding to 12114041100 its reverse (114041121), we get a palindrome (12228082221).
The spelling of 12114041100 in words is "twelve billion, one hundred fourteen million, forty-one thousand, one hundred".
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