1211421314232 has 48 divisors (see below), whose sum is σ = 3336541767000. Its totient is φ = 396962915136.

The previous prime is 1211421314111. The next prime is 1211421314261. The reversal of 1211421314232 is 2324131241121.

1211421314232 is a `hidden beast` number, since 1 + 2 + 1 + 1 + 421 + 3 + 1 + 4 + 232 = 666.

It is a super-3 number, since 3×1211421314232³ (a number of 37 digits) contains 333 as substring.

It is a nude number because it is divisible by every one of its digits.

It is a junction number, because it is equal to n+sod(n) for n = 1211421314196 and 1211421314205.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 142583007 + ... + 142591502.

Almost surely, 2^{1211421314232} is an apocalyptic number.

1211421314232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1211421314232 is an abundant number, since it is smaller than the sum of its proper divisors (2125120452768).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1211421314232 is a wasteful number, since it uses less digits than its factorization.

1211421314232 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 285174580 (or 285174573 counting only the distinct ones).

The product of its digits is 2304, while the sum is 27.

Adding to 1211421314232 its reverse (2324131241121), we get a palindrome (3535552555353).

The spelling of 1211421314232 in words is "one trillion, two hundred eleven billion, four hundred twenty-one million, three hundred fourteen thousand, two hundred thirty-two".