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12120121589 is a prime number
BaseRepresentation
bin10110100100110101…
…00110000011110101
31011021200010222012012
423102122212003311
5144310222342324
65322400134005
7606230222312
oct132232460365
934250128165
1012120121589
11515a546814
122423007305
1311b2001ba4
1482d969d09
154ae09c20e
hex2d26a60f5

12120121589 has 2 divisors, whose sum is σ = 12120121590. Its totient is φ = 12120121588.

The previous prime is 12120121547. The next prime is 12120121591. The reversal of 12120121589 is 98512102121.

12120121589 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7796007025 + 4324114564 = 88295^2 + 65758^2 .

It is an emirp because it is prime and its reverse (98512102121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12120121589 - 28 = 12120121333 is a prime.

Together with 12120121591, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12120121289) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060060794 + 6060060795.

It is an arithmetic number, because the mean of its divisors is an integer number (6060060795).

Almost surely, 212120121589 is an apocalyptic number.

It is an amenable number.

12120121589 is a deficient number, since it is larger than the sum of its proper divisors (1).

12120121589 is an equidigital number, since it uses as much as digits as its factorization.

12120121589 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 32.

The spelling of 12120121589 in words is "twelve billion, one hundred twenty million, one hundred twenty-one thousand, five hundred eighty-nine".