Base | Representation |
---|---|
bin | 10001101000110001100… |
… | …011101000010000101111 |
3 | 11021212102012210010222001 |
4 | 101220301203220100233 |
5 | 124324200110413012 |
6 | 2324442443433131 |
7 | 153364535504146 |
oct | 21506143502057 |
9 | 4255365703861 |
10 | 1212012201007 |
11 | 428014321543 |
12 | 176a905257a7 |
13 | 8a3a5131b5a |
14 | 42939a0075d |
15 | 217d956b357 |
hex | 11a318e842f |
1212012201007 has 2 divisors, whose sum is σ = 1212012201008. Its totient is φ = 1212012201006.
The previous prime is 1212012200983. The next prime is 1212012201031. The reversal of 1212012201007 is 7001022102121.
It is a balanced prime because it is at equal distance from previous prime (1212012200983) and next prime (1212012201031).
It is an emirp because it is prime and its reverse (7001022102121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1212012201007 - 215 = 1212012168239 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1212012201047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606006100503 + 606006100504.
It is an arithmetic number, because the mean of its divisors is an integer number (606006100504).
Almost surely, 21212012201007 is an apocalyptic number.
1212012201007 is a deficient number, since it is larger than the sum of its proper divisors (1).
1212012201007 is an equidigital number, since it uses as much as digits as its factorization.
1212012201007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 19.
Adding to 1212012201007 its reverse (7001022102121), we get a palindrome (8213034303128).
The spelling of 1212012201007 in words is "one trillion, two hundred twelve billion, twelve million, two hundred one thousand, seven".
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