Base | Representation |
---|---|
bin | 1011000001011111010011… |
… | …0111110000101100111111 |
3 | 1120220200101100021122001102 |
4 | 2300113310313300230333 |
5 | 3042034143004001002 |
6 | 41435540441003315 |
7 | 2360441061445436 |
oct | 260276467605477 |
9 | 46820340248042 |
10 | 12120211000127 |
11 | 395317515549a |
12 | 1438b8a18353b |
13 | 69bc145130a9 |
14 | 2dc89ad6c11d |
15 | 16041b6a4a02 |
hex | b05f4df0b3f |
12120211000127 has 2 divisors, whose sum is σ = 12120211000128. Its totient is φ = 12120211000126.
The previous prime is 12120211000087. The next prime is 12120211000151. The reversal of 12120211000127 is 72100011202121.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12120211000127 - 224 = 12120194222911 is a prime.
It is a super-2 number, since 2×121202110001272 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12120211000099 and 12120211000108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12120211003127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060105500063 + 6060105500064.
It is an arithmetic number, because the mean of its divisors is an integer number (6060105500064).
Almost surely, 212120211000127 is an apocalyptic number.
12120211000127 is a deficient number, since it is larger than the sum of its proper divisors (1).
12120211000127 is an equidigital number, since it uses as much as digits as its factorization.
12120211000127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 20.
Adding to 12120211000127 its reverse (72100011202121), we get a palindrome (84220222202248).
The spelling of 12120211000127 in words is "twelve trillion, one hundred twenty billion, two hundred eleven million, one hundred twenty-seven", and thus it is an aban number.
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