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12120221212117 is a prime number
BaseRepresentation
bin1011000001011111010101…
…1110101101110111010101
31120220200102001111110021021
42300113311132231313111
53042034203112241432
641435541443521141
72360441244320134
oct260276536556725
946820361443237
1012120221212117
11395317a99a957
121438b916891b1
1369bc1667a2a5
142dc89c46991b
1516041c520697
hexb05f57addd5

12120221212117 has 2 divisors, whose sum is σ = 12120221212118. Its totient is φ = 12120221212116.

The previous prime is 12120221212081. The next prime is 12120221212313. The reversal of 12120221212117 is 71121212202121.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12117354038001 + 2867174116 = 3480999^2 + 53546^2 .

It is a cyclic number.

It is not a de Polignac number, because 12120221212117 - 215 = 12120221179349 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12120221212091 and 12120221212100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12120221512117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060110606058 + 6060110606059.

It is an arithmetic number, because the mean of its divisors is an integer number (6060110606059).

Almost surely, 212120221212117 is an apocalyptic number.

It is an amenable number.

12120221212117 is a deficient number, since it is larger than the sum of its proper divisors (1).

12120221212117 is an equidigital number, since it uses as much as digits as its factorization.

12120221212117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 448, while the sum is 25.

Adding to 12120221212117 its reverse (71121212202121), we get a palindrome (83241433414238).

The spelling of 12120221212117 in words is "twelve trillion, one hundred twenty billion, two hundred twenty-one million, two hundred twelve thousand, one hundred seventeen".