Base | Representation |
---|---|
bin | 1011000001100000100011… |
… | …0100111110001110010111 |
3 | 1120220201020200021220111222 |
4 | 2300120020310332032113 |
5 | 3042040334212012044 |
6 | 41440034001120555 |
7 | 2360452265351432 |
oct | 260301064761627 |
9 | 46821220256458 |
10 | 12120545813399 |
11 | 3953327147681 |
12 | 143906232915b |
13 | 69bc689ac95a |
14 | 2dc8cd604819 |
15 | 16043ac8d8ee |
hex | b0608d3e397 |
12120545813399 has 2 divisors, whose sum is σ = 12120545813400. Its totient is φ = 12120545813398.
The previous prime is 12120545813377. The next prime is 12120545813401. The reversal of 12120545813399 is 99331854502121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12120545813399 - 28 = 12120545813143 is a prime.
Together with 12120545813401, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12120545813399.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12120545818399) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060272906699 + 6060272906700.
It is an arithmetic number, because the mean of its divisors is an integer number (6060272906700).
Almost surely, 212120545813399 is an apocalyptic number.
12120545813399 is a deficient number, since it is larger than the sum of its proper divisors (1).
12120545813399 is an equidigital number, since it uses as much as digits as its factorization.
12120545813399 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2332800, while the sum is 53.
The spelling of 12120545813399 in words is "twelve trillion, one hundred twenty billion, five hundred forty-five million, eight hundred thirteen thousand, three hundred ninety-nine".
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