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12121041234013 is a prime number
BaseRepresentation
bin1011000001100010011001…
…0110110110100001011101
31120220202112012111212211121
42300120212112312201131
53042042343023442023
641440155055450541
72360500462353415
oct260304626664135
946822465455747
1012121041234013
1139535608664a8
121439180226a51
1369c01752054a
142dc939327645
151604694eed5d
hexb06265b685d

12121041234013 has 2 divisors, whose sum is σ = 12121041234014. Its totient is φ = 12121041234012.

The previous prime is 12121041234007. The next prime is 12121041234019. The reversal of 12121041234013 is 31043214012121.

It is a balanced prime because it is at equal distance from previous prime (12121041234007) and next prime (12121041234019).

It can be written as a sum of positive squares in only one way, i.e., 11861941909689 + 259099324324 = 3444117^2 + 509018^2 .

It is a cyclic number.

It is not a de Polignac number, because 12121041234013 - 225 = 12121007679581 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12121041234019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060520617006 + 6060520617007.

It is an arithmetic number, because the mean of its divisors is an integer number (6060520617007).

Almost surely, 212121041234013 is an apocalyptic number.

It is an amenable number.

12121041234013 is a deficient number, since it is larger than the sum of its proper divisors (1).

12121041234013 is an equidigital number, since it uses as much as digits as its factorization.

12121041234013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 12121041234013 its reverse (31043214012121), we get a palindrome (43164255246134).

The spelling of 12121041234013 in words is "twelve trillion, one hundred twenty-one billion, forty-one million, two hundred thirty-four thousand, thirteen".