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1212131333131 is a prime number
BaseRepresentation
bin10001101000111000101…
…010000101010000001011
311021212201111221200111221
4101220320222011100023
5124324421110130011
62324502341102511
7153400513222135
oct21507052052013
94255644850457
101212131333131
114280755a0244
12176b043b7a37
138a3c3a13a34
144294b772055
15217e4c4e971
hex11a38a8540b

1212131333131 has 2 divisors, whose sum is σ = 1212131333132. Its totient is φ = 1212131333130.

The previous prime is 1212131333129. The next prime is 1212131333251. The reversal of 1212131333131 is 1313331312121.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1212131333131 - 21 = 1212131333129 is a prime.

It is a super-2 number, since 2×12121313331312 (a number of 25 digits) contains 22 as substring.

Together with 1212131333129, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1212131333096 and 1212131333105.

It is not a weakly prime, because it can be changed into another prime (1212111333131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606065666565 + 606065666566.

It is an arithmetic number, because the mean of its divisors is an integer number (606065666566).

Almost surely, 21212131333131 is an apocalyptic number.

1212131333131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1212131333131 is an equidigital number, since it uses as much as digits as its factorization.

1212131333131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 972, while the sum is 25.

Adding to 1212131333131 its reverse (1313331312121), we get a palindrome (2525462645252).

The spelling of 1212131333131 in words is "one trillion, two hundred twelve billion, one hundred thirty-one million, three hundred thirty-three thousand, one hundred thirty-one".