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121301340044207 is a prime number
BaseRepresentation
bin11011100101001010101011…
…010010001011101110101111
3120220111021221221122210020112
4123211022223102023232233
5111344400121022403312
61105553022154210235
734356506200100141
oct3345125322135657
9526437857583215
10121301340044207
1135717678154454
121173101942397b
13528b88a03ca7b
1421d50325a0c91
15e054d602ad22
hex6e52ab48bbaf

121301340044207 has 2 divisors, whose sum is σ = 121301340044208. Its totient is φ = 121301340044206.

The previous prime is 121301340044197. The next prime is 121301340044239. The reversal of 121301340044207 is 702440043103121.

It is an a-pointer prime, because the next prime (121301340044239) can be obtained adding 121301340044207 to its sum of digits (32).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 121301340044207 - 28 = 121301340043951 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121301340044407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60650670022103 + 60650670022104.

It is an arithmetic number, because the mean of its divisors is an integer number (60650670022104).

Almost surely, 2121301340044207 is an apocalyptic number.

121301340044207 is a deficient number, since it is larger than the sum of its proper divisors (1).

121301340044207 is an equidigital number, since it uses as much as digits as its factorization.

121301340044207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16128, while the sum is 32.

Adding to 121301340044207 its reverse (702440043103121), we get a palindrome (823741383147328).

The spelling of 121301340044207 in words is "one hundred twenty-one trillion, three hundred one billion, three hundred forty million, forty-four thousand, two hundred seven".