Base | Representation |
---|---|
bin | 11011100101001010101011… |
… | …010010001011101110101111 |
3 | 120220111021221221122210020112 |
4 | 123211022223102023232233 |
5 | 111344400121022403312 |
6 | 1105553022154210235 |
7 | 34356506200100141 |
oct | 3345125322135657 |
9 | 526437857583215 |
10 | 121301340044207 |
11 | 35717678154454 |
12 | 1173101942397b |
13 | 528b88a03ca7b |
14 | 21d50325a0c91 |
15 | e054d602ad22 |
hex | 6e52ab48bbaf |
121301340044207 has 2 divisors, whose sum is σ = 121301340044208. Its totient is φ = 121301340044206.
The previous prime is 121301340044197. The next prime is 121301340044239. The reversal of 121301340044207 is 702440043103121.
It is an a-pointer prime, because the next prime (121301340044239) can be obtained adding 121301340044207 to its sum of digits (32).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 121301340044207 - 28 = 121301340043951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121301340044407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60650670022103 + 60650670022104.
It is an arithmetic number, because the mean of its divisors is an integer number (60650670022104).
Almost surely, 2121301340044207 is an apocalyptic number.
121301340044207 is a deficient number, since it is larger than the sum of its proper divisors (1).
121301340044207 is an equidigital number, since it uses as much as digits as its factorization.
121301340044207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 32.
Adding to 121301340044207 its reverse (702440043103121), we get a palindrome (823741383147328).
The spelling of 121301340044207 in words is "one hundred twenty-one trillion, three hundred one billion, three hundred forty million, forty-four thousand, two hundred seven".
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