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1213022014117 is a prime number
BaseRepresentation
bin10001101001101101101…
…111110000101010100101
311021222000120220222010121
4101221231233300222211
5124333232113422432
62325130555321541
7153431546665534
oct21515557605245
94258016828117
101213022014117
11428492338031
121771127502b1
138a5063c67c4
14429d3b8431b
152184803a197
hex11a6dbf0aa5

1213022014117 has 2 divisors, whose sum is σ = 1213022014118. Its totient is φ = 1213022014116.

The previous prime is 1213022014109. The next prime is 1213022014147. The reversal of 1213022014117 is 7114102203121.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1207535056641 + 5486957476 = 1098879^2 + 74074^2 .

It is a cyclic number.

It is not a de Polignac number, because 1213022014117 - 23 = 1213022014109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1213022014091 and 1213022014100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1213022014147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606511007058 + 606511007059.

It is an arithmetic number, because the mean of its divisors is an integer number (606511007059).

Almost surely, 21213022014117 is an apocalyptic number.

It is an amenable number.

1213022014117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213022014117 is an equidigital number, since it uses as much as digits as its factorization.

1213022014117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 672, while the sum is 25.

Adding to 1213022014117 its reverse (7114102203121), we get a palindrome (8327124217238).

The spelling of 1213022014117 in words is "one trillion, two hundred thirteen billion, twenty-two million, fourteen thousand, one hundred seventeen".