Base | Representation |
---|---|
bin | 10001101001110010011… |
… | …001110000010110001011 |
3 | 11021222020000220202100021 |
4 | 101221302121300112023 |
5 | 124333412113203343 |
6 | 2325142425521311 |
7 | 153433515661624 |
oct | 21516231602613 |
9 | 4258200822307 |
10 | 1213100131723 |
11 | 428522442a37 |
12 | 177134943237 |
13 | 8a51964813c |
14 | 42a002baa4b |
15 | 2184ed1b0ed |
hex | 11a7267058b |
1213100131723 has 2 divisors, whose sum is σ = 1213100131724. Its totient is φ = 1213100131722.
The previous prime is 1213100131721. The next prime is 1213100131759. The reversal of 1213100131723 is 3271310013121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1213100131723 - 21 = 1213100131721 is a prime.
It is a super-2 number, since 2×12131001317232 (a number of 25 digits) contains 22 as substring.
Together with 1213100131721, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1213100131721) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606550065861 + 606550065862.
It is an arithmetic number, because the mean of its divisors is an integer number (606550065862).
Almost surely, 21213100131723 is an apocalyptic number.
1213100131723 is a deficient number, since it is larger than the sum of its proper divisors (1).
1213100131723 is an equidigital number, since it uses as much as digits as its factorization.
1213100131723 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 756, while the sum is 25.
Adding to 1213100131723 its reverse (3271310013121), we get a palindrome (4484410144844).
The spelling of 1213100131723 in words is "one trillion, two hundred thirteen billion, one hundred million, one hundred thirty-one thousand, seven hundred twenty-three".
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