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1213100131759 is a prime number
BaseRepresentation
bin10001101001110010011…
…001110000010110101111
311021222020000220202101121
4101221302121300112233
5124333412113204014
62325142425521411
7153433515662005
oct21516231602657
94258200822347
101213100131759
11428522442a6a
12177134943267
138a519648169
1442a002baa75
152184ed1b124
hex11a726705af

1213100131759 has 2 divisors, whose sum is σ = 1213100131760. Its totient is φ = 1213100131758.

The previous prime is 1213100131723. The next prime is 1213100131829. The reversal of 1213100131759 is 9571310013121.

It is a weak prime.

It is an emirp because it is prime and its reverse (9571310013121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1213100131759 - 213 = 1213100123567 is a prime.

It is a super-2 number, since 2×12131001317592 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1213100131259) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606550065879 + 606550065880.

It is an arithmetic number, because the mean of its divisors is an integer number (606550065880).

Almost surely, 21213100131759 is an apocalyptic number.

1213100131759 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213100131759 is an equidigital number, since it uses as much as digits as its factorization.

1213100131759 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5670, while the sum is 34.

The spelling of 1213100131759 in words is "one trillion, two hundred thirteen billion, one hundred million, one hundred thirty-one thousand, seven hundred fifty-nine".