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1213200011081 is a prime number
BaseRepresentation
bin10001101001111000010…
…110110000111101001001
311021222110222212011001202
4101221320112300331021
5124334113200323311
62325200354353545
7153436140642242
oct21517026607511
94258428764052
101213200011081
11428573861863
1217716228b8b5
138a534248a56
1442a0d679cc9
1521858999e3b
hex11a785b0f49

1213200011081 has 2 divisors, whose sum is σ = 1213200011082. Its totient is φ = 1213200011080.

The previous prime is 1213200011063. The next prime is 1213200011083. The reversal of 1213200011081 is 1801100023121.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1013426769481 + 199773241600 = 1006691^2 + 446960^2 .

It is a cyclic number.

It is not a de Polignac number, because 1213200011081 - 214 = 1213199994697 is a prime.

It is a super-3 number, since 3×12132000110813 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 1213200011083, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1213200011083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606600005540 + 606600005541.

It is an arithmetic number, because the mean of its divisors is an integer number (606600005541).

Almost surely, 21213200011081 is an apocalyptic number.

It is an amenable number.

1213200011081 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213200011081 is an equidigital number, since it uses as much as digits as its factorization.

1213200011081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 20.

The spelling of 1213200011081 in words is "one trillion, two hundred thirteen billion, two hundred million, eleven thousand, eighty-one".