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121320312013032 = 23311459546636413
BaseRepresentation
bin11011100101011100010110…
…000110100000000011101000
3120220120002221010202122211120
4123211130112012200003220
5111400202444333404112
61110005440521255240
734361050300134456
oct3345342606400350
9526502833678746
10121320312013032
1135724723354430
1211734833034520
1352905c1744722
1421d5d1211d9d6
15e05c468c9e8c
hex6e57161a00e8

121320312013032 has 32 divisors (see below), whose sum is σ = 330873578218080. Its totient is φ = 36763730912960.

The previous prime is 121320312013013. The next prime is 121320312013037. The reversal of 121320312013032 is 230310213023121.

It is a super-2 number, since 2×1213203120130322 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a junction number, because it is equal to n+sod(n) for n = 121320312012993 and 121320312013011.

It is not an unprimeable number, because it can be changed into a prime (121320312013037) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 229773317943 + ... + 229773318470.

It is an arithmetic number, because the mean of its divisors is an integer number (10339799319315).

Almost surely, 2121320312013032 is an apocalyptic number.

121320312013032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

121320312013032 is an abundant number, since it is smaller than the sum of its proper divisors (209553266205048).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

121320312013032 is a wasteful number, since it uses less digits than its factorization.

121320312013032 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 459546636433 (or 459546636429 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 121320312013032 its reverse (230310213023121), we get a palindrome (351630525036153).

The spelling of 121320312013032 in words is "one hundred twenty-one trillion, three hundred twenty billion, three hundred twelve million, thirteen thousand, thirty-two".

Divisors: 1 2 3 4 6 8 11 12 22 24 33 44 66 88 132 264 459546636413 919093272826 1378639909239 1838186545652 2757279818478 3676373091304 5055013000543 5514559636956 10110026001086 11029119273912 15165039001629 20220052002172 30330078003258 40440104004344 60660156006516 121320312013032