Base | Representation |
---|---|
bin | 11011100101011110111110… |
… | …001000100000001110111010 |
3 | 120220120101012121101122022121 |
4 | 123211132332020200032322 |
5 | 111400224233031012310 |
6 | 1110011024344311454 |
7 | 34361210201102152 |
oct | 3345367610401672 |
9 | 526511177348277 |
10 | 121323131110330 |
11 | 3572593a695a06 |
12 | 1173529b17258a |
13 | 52909507ca236 |
14 | 21d60dc6b5762 |
15 | e05d5e1380da |
hex | 6e57be2203ba |
121323131110330 has 32 divisors (see below), whose sum is σ = 218545921670400. Its totient is φ = 48492747905472.
The previous prime is 121323131110309. The next prime is 121323131110343. The reversal of 121323131110330 is 33011131323121.
It is a junction number, because it is equal to n+sod(n) for n = 121323131110295 and 121323131110304.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 302457441 + ... + 302858299.
It is an arithmetic number, because the mean of its divisors is an integer number (6829560052200).
Almost surely, 2121323131110330 is an apocalyptic number.
121323131110330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
121323131110330 is a deficient number, since it is larger than the sum of its proper divisors (97222790560070).
121323131110330 is a wasteful number, since it uses less digits than its factorization.
121323131110330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 423558.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 121323131110330 its reverse (33011131323121), we get a palindrome (154334262433451).
The spelling of 121323131110330 in words is "one hundred twenty-one trillion, three hundred twenty-three billion, one hundred thirty-one million, one hundred ten thousand, three hundred thirty".
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