Base | Representation |
---|---|
bin | 1011000010010000001011… |
… | …1001110110110000101110 |
3 | 1120221221020201111120000012 |
4 | 2300210002321312300232 |
5 | 3042243030310112032 |
6 | 41445550411133222 |
7 | 2361414155436326 |
oct | 260440271666056 |
9 | 46857221446005 |
10 | 12133331332142 |
11 | 3958798249099 |
12 | 143b630144212 |
13 | 6a02257c6b67 |
14 | 2dd38369c286 |
15 | 1609384756b2 |
hex | b0902e76c2e |
12133331332142 has 4 divisors (see below), whose sum is σ = 18199996998216. Its totient is φ = 6066665666070.
The previous prime is 12133331332121. The next prime is 12133331332147. The reversal of 12133331332142 is 24123313333121.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 12133331332099 and 12133331332108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12133331332147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3033332833034 + ... + 3033332833037.
It is an arithmetic number, because the mean of its divisors is an integer number (4549999249554).
Almost surely, 212133331332142 is an apocalyptic number.
12133331332142 is a deficient number, since it is larger than the sum of its proper divisors (6066665666074).
12133331332142 is an equidigital number, since it uses as much as digits as its factorization.
12133331332142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6066665666073.
The product of its digits is 23328, while the sum is 32.
Adding to 12133331332142 its reverse (24123313333121), we get a palindrome (36256644665263).
The spelling of 12133331332142 in words is "twelve trillion, one hundred thirty-three billion, three hundred thirty-one million, three hundred thirty-two thousand, one hundred forty-two".
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