Base | Representation |
---|---|
bin | 10001101010000110111… |
… | …001100011010001101111 |
3 | 11022000002222222122012012 |
4 | 101222012321203101233 |
5 | 124340113131323434 |
6 | 2325240512231435 |
7 | 153445162624514 |
oct | 21520671432157 |
9 | 4260088878165 |
10 | 1213444011119 |
11 | 42868956768a |
12 | 17720bb3b57b |
13 | 8a57296a482 |
14 | 42a33c3330b |
15 | 218700e63ce |
hex | 11a86e6346f |
1213444011119 has 2 divisors, whose sum is σ = 1213444011120. Its totient is φ = 1213444011118.
The previous prime is 1213444011103. The next prime is 1213444011121. The reversal of 1213444011119 is 9111104443121.
It is a strong prime.
It is an emirp because it is prime and its reverse (9111104443121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1213444011119 - 24 = 1213444011103 is a prime.
It is a super-2 number, since 2×12134440111192 (a number of 25 digits) contains 22 as substring.
Together with 1213444011121, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1213444011919) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606722005559 + 606722005560.
It is an arithmetic number, because the mean of its divisors is an integer number (606722005560).
Almost surely, 21213444011119 is an apocalyptic number.
1213444011119 is a deficient number, since it is larger than the sum of its proper divisors (1).
1213444011119 is an equidigital number, since it uses as much as digits as its factorization.
1213444011119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 32.
The spelling of 1213444011119 in words is "one trillion, two hundred thirteen billion, four hundred forty-four million, eleven thousand, one hundred nineteen".
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