Base | Representation |
---|---|
bin | 11011100111001100001100… |
… | …000011000000101110100111 |
3 | 120220222120220110000221012221 |
4 | 123213030030003000232213 |
5 | 111404134421004113112 |
6 | 1110140541203253211 |
7 | 34402531244516203 |
oct | 3347141403005647 |
9 | 526876813027187 |
10 | 121440402410407 |
11 | 35770649241423 |
12 | 11753b6907a207 |
13 | 529ba1c58c862 |
14 | 21dba65477b03 |
15 | e08e24789e07 |
hex | 6e730c0c0ba7 |
121440402410407 has 2 divisors, whose sum is σ = 121440402410408. Its totient is φ = 121440402410406.
The previous prime is 121440402410401. The next prime is 121440402410413. The reversal of 121440402410407 is 704014204044121.
It is a balanced prime because it is at equal distance from previous prime (121440402410401) and next prime (121440402410413).
It is a cyclic number.
It is not a de Polignac number, because 121440402410407 - 27 = 121440402410279 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121440402410401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60720201205203 + 60720201205204.
It is an arithmetic number, because the mean of its divisors is an integer number (60720201205204).
Almost surely, 2121440402410407 is an apocalyptic number.
121440402410407 is a deficient number, since it is larger than the sum of its proper divisors (1).
121440402410407 is an equidigital number, since it uses as much as digits as its factorization.
121440402410407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28672, while the sum is 34.
Adding to 121440402410407 its reverse (704014204044121), we get a palindrome (825454606454528).
The spelling of 121440402410407 in words is "one hundred twenty-one trillion, four hundred forty billion, four hundred two million, four hundred ten thousand, four hundred seven".
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