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1214524040113 is a prime number
BaseRepresentation
bin10001101011000111010…
…001100010001110110001
311022002220021020210110001
4101223013101202032301
5124344321123240423
62325540013110001
7153514016002216
oct21530721421661
94262807223401
101214524040113
1142909318142a
12177471788301
138a6b5647c97
1442ad7453b0d
15218d4d34cad
hex11ac74623b1

1214524040113 has 2 divisors, whose sum is σ = 1214524040114. Its totient is φ = 1214524040112.

The previous prime is 1214524040111. The next prime is 1214524040137. The reversal of 1214524040113 is 3110404254121.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 803473798689 + 411050241424 = 896367^2 + 641132^2 .

It is a cyclic number.

It is not a de Polignac number, because 1214524040113 - 21 = 1214524040111 is a prime.

Together with 1214524040111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1214524040111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607262020056 + 607262020057.

It is an arithmetic number, because the mean of its divisors is an integer number (607262020057).

Almost surely, 21214524040113 is an apocalyptic number.

It is an amenable number.

1214524040113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1214524040113 is an equidigital number, since it uses as much as digits as its factorization.

1214524040113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3840, while the sum is 28.

Adding to 1214524040113 its reverse (3110404254121), we get a palindrome (4324928294234).

The spelling of 1214524040113 in words is "one trillion, two hundred fourteen billion, five hundred twenty-four million, forty thousand, one hundred thirteen".