1214524040111 has 2 divisors, whose sum is σ = 1214524040112. Its totient is φ = 1214524040110.

The previous prime is 1214524040099. The next prime is 1214524040113. The reversal of 1214524040111 is 1110404254121.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1214524040111 - 2¹⁰ = 1214524039087 is a prime.

It is a super-4 number, since 4×1214524040111⁴ (a number of 49 digits) contains 4444 as substring.

Together with 1214524040113, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1214524040113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607262020055 + 607262020056.

It is an arithmetic number, because the mean of its divisors is an integer number (607262020056).

Almost surely, 2^{1214524040111} is an apocalyptic number.

1214524040111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1214524040111 is an equidigital number, since it uses as much as digits as its factorization.

1214524040111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1280, while the sum is 26.

Adding to 1214524040111 its reverse (1110404254121), we get a palindrome (2324928294232).

The spelling of 1214524040111 in words is "one trillion, two hundred fourteen billion, five hundred twenty-four million, forty thousand, one hundred eleven".