Base | Representation |
---|---|
bin | 10001110000010100010… |
… | …010110111001111000100 |
3 | 11022122022122110222121220 |
4 | 101300110102313033010 |
5 | 124442241431414340 |
6 | 2332302241240340 |
7 | 154102331043522 |
oct | 21602422671704 |
9 | 4278278428556 |
10 | 1220111201220 |
11 | 43049aa6824a |
12 | 1785709330b0 |
13 | 8b096028682 |
14 | 430a74b9312 |
15 | 21b105beed0 |
hex | 11c144b73c4 |
1220111201220 has 48 divisors (see below), whose sum is σ = 3439239652800. Its totient is φ = 323179340416.
The previous prime is 1220111201213. The next prime is 1220111201237. The reversal of 1220111201220 is 221021110221.
It is a super-2 number, since 2×12201112012202 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 1220111201220.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 68229942 + ... + 68247821.
It is an arithmetic number, because the mean of its divisors is an integer number (71650826100).
Almost surely, 21220111201220 is an apocalyptic number.
1220111201220 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1220111201220 is an abundant number, since it is smaller than the sum of its proper divisors (2219128451580).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1220111201220 is a wasteful number, since it uses less digits than its factorization.
1220111201220 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 136477924 (or 136477922 counting only the distinct ones).
The product of its (nonzero) digits is 32, while the sum is 15.
Adding to 1220111201220 its reverse (221021110221), we get a palindrome (1441132311441).
Subtracting from 1220111201220 its reverse (221021110221), we obtain a palindrome (999090090999).
It can be divided in two parts, 122011 and 1201220, that added together give a palindrome (1323231).
The spelling of 1220111201220 in words is "one trillion, two hundred twenty billion, one hundred eleven million, two hundred one thousand, two hundred twenty".
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