Base | Representation |
---|---|
bin | 1011000110001101110001… |
… | …0000110111110100111111 |
3 | 1121012102221201110202022110 |
4 | 2301203130100313310333 |
5 | 3044401433021444020 |
6 | 41541125201145103 |
7 | 2366344062203406 |
oct | 261433420676477 |
9 | 47172851422273 |
10 | 12201402531135 |
11 | 3984649703444 |
12 | 145086902b193 |
13 | 6a678346562c |
14 | 3027a007063d |
15 | 1625be5898e0 |
hex | b18dc437d3f |
12201402531135 has 64 divisors (see below), whose sum is σ = 21387254878080. Its totient is φ = 5912363089920.
The previous prime is 12201402531127. The next prime is 12201402531137. The reversal of 12201402531135 is 53113520410221.
It is a happy number.
It is not a de Polignac number, because 12201402531135 - 23 = 12201402531127 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12201402531137) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 41568949 + ... + 41861441.
It is an arithmetic number, because the mean of its divisors is an integer number (334175857470).
Almost surely, 212201402531135 is an apocalyptic number.
12201402531135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12201402531135 is a deficient number, since it is larger than the sum of its proper divisors (9185852346945).
12201402531135 is a wasteful number, since it uses less digits than its factorization.
12201402531135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 298188.
The product of its (nonzero) digits is 7200, while the sum is 30.
Adding to 12201402531135 its reverse (53113520410221), we get a palindrome (65314922941356).
The spelling of 12201402531135 in words is "twelve trillion, two hundred one billion, four hundred two million, five hundred thirty-one thousand, one hundred thirty-five".
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