Base | Representation |
---|---|
bin | 10001110000100001100… |
… | …100110001110000110111 |
3 | 11022122220011201101202021 |
4 | 101300201210301300313 |
5 | 124443221001014312 |
6 | 2332340320454011 |
7 | 154111004601256 |
oct | 21604144616067 |
9 | 4278804641667 |
10 | 1220334001207 |
11 | 4305a4803172 |
12 | 17861347a307 |
13 | 8b100236699 |
14 | 430c8d1479d |
15 | 21b24e2ec07 |
hex | 11c21931c37 |
1220334001207 has 2 divisors, whose sum is σ = 1220334001208. Its totient is φ = 1220334001206.
The previous prime is 1220334001193. The next prime is 1220334001259. The reversal of 1220334001207 is 7021004330221.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1220334001207 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1220334001267) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610167000603 + 610167000604.
It is an arithmetic number, because the mean of its divisors is an integer number (610167000604).
Almost surely, 21220334001207 is an apocalyptic number.
1220334001207 is a deficient number, since it is larger than the sum of its proper divisors (1).
1220334001207 is an equidigital number, since it uses as much as digits as its factorization.
1220334001207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 25.
Adding to 1220334001207 its reverse (7021004330221), we get a palindrome (8241338331428).
The spelling of 1220334001207 in words is "one trillion, two hundred twenty billion, three hundred thirty-four million, one thousand, two hundred seven".
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