Base | Representation |
---|---|
bin | 10001110000101000000… |
… | …110001001100000100111 |
3 | 11022200011210121001212002 |
4 | 101300220012021200213 |
5 | 124443432003200034 |
6 | 2332355225515515 |
7 | 154113503561552 |
oct | 21605006114047 |
9 | 4280153531762 |
10 | 1220443412519 |
11 | 430650542541 |
12 | 178644042b9b |
13 | 8b119ac3ac6 |
14 | 430d9675699 |
15 | 21b2e842e7e |
hex | 11c28189827 |
1220443412519 has 2 divisors, whose sum is σ = 1220443412520. Its totient is φ = 1220443412518.
The previous prime is 1220443412497. The next prime is 1220443412521. The reversal of 1220443412519 is 9152143440221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1220443412519 - 212 = 1220443408423 is a prime.
It is a super-2 number, since 2×12204434125192 (a number of 25 digits) contains 22 as substring.
Together with 1220443412521, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1220443411519) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610221706259 + 610221706260.
It is an arithmetic number, because the mean of its divisors is an integer number (610221706260).
Almost surely, 21220443412519 is an apocalyptic number.
1220443412519 is a deficient number, since it is larger than the sum of its proper divisors (1).
1220443412519 is an equidigital number, since it uses as much as digits as its factorization.
1220443412519 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 69120, while the sum is 38.
The spelling of 1220443412519 in words is "one trillion, two hundred twenty billion, four hundred forty-three million, four hundred twelve thousand, five hundred nineteen".
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