Base | Representation |
---|---|
bin | 111000110110111000… |
… | …0101000110111100101 |
3 | 102200011101201122221212 |
4 | 1301231300220313211 |
5 | 4000030220114031 |
6 | 132031530321205 |
7 | 11551523363132 |
oct | 1615560506745 |
9 | 380141648855 |
10 | 122100551141 |
11 | 4786763a2a8 |
12 | 1b7b7289205 |
13 | b68b43903a |
14 | 5ca42d7589 |
15 | 32995cb12b |
hex | 1c6dc28de5 |
122100551141 has 2 divisors, whose sum is σ = 122100551142. Its totient is φ = 122100551140.
The previous prime is 122100551123. The next prime is 122100551159. The reversal of 122100551141 is 141155001221.
It is a happy number.
It is a balanced prime because it is at equal distance from previous prime (122100551123) and next prime (122100551159).
It can be written as a sum of positive squares in only one way, i.e., 110426613025 + 11673938116 = 332305^2 + 108046^2 .
It is a cyclic number.
It is not a de Polignac number, because 122100551141 - 230 = 121026809317 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (122100551641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61050275570 + 61050275571.
It is an arithmetic number, because the mean of its divisors is an integer number (61050275571).
Almost surely, 2122100551141 is an apocalyptic number.
It is an amenable number.
122100551141 is a deficient number, since it is larger than the sum of its proper divisors (1).
122100551141 is an equidigital number, since it uses as much as digits as its factorization.
122100551141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 400, while the sum is 23.
Adding to 122100551141 its reverse (141155001221), we get a palindrome (263255552362).
The spelling of 122100551141 in words is "one hundred twenty-two billion, one hundred million, five hundred fifty-one thousand, one hundred forty-one".
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