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12210300210312 = 23324713127543853
BaseRepresentation
bin1011000110101110111010…
…0110110100110010001000
31121020021220211000200112200
42301223232212310302020
53100023143323212222
641545200125240200
72400110423215131
oct261535646646210
947207824020480
1012210300210312
1139883a5168506
121452530a03060
136a757096b959
14302da5a4cc88
151629407a3eac
hexb1aee9b4c88

12210300210312 has 96 divisors (see below), whose sum is σ = 34030982494080. Its totient is φ = 3953093639040.

The previous prime is 12210300210293. The next prime is 12210300210313. The reversal of 12210300210312 is 21301200301221.

12210300210312 is a `hidden beast` number, since 1 + 22 + 10 + 300 + 21 + 0 + 312 = 666.

12210300210312 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×122103002103122 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (12210300210313) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 13328623 + ... + 14215230.

It is an arithmetic number, because the mean of its divisors is an integer number (354489400980).

Almost surely, 212210300210312 is an apocalyptic number.

12210300210312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

12210300210312 is an abundant number, since it is smaller than the sum of its proper divisors (21820682283768).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12210300210312 is a wasteful number, since it uses less digits than its factorization.

12210300210312 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27544043 (or 27544036 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 12210300210312 its reverse (21301200301221), we get a palindrome (33511500511533).

Subtracting 12210300210312 from its reverse (21301200301221), we obtain a palindrome (9090900090909).

The spelling of 12210300210312 in words is "twelve trillion, two hundred ten billion, three hundred million, two hundred ten thousand, three hundred twelve".

Divisors: 1 2 3 4 6 8 9 12 18 24 36 47 72 94 131 141 188 262 282 376 393 423 524 564 786 846 1048 1128 1179 1572 1692 2358 3144 3384 4716 6157 9432 12314 18471 24628 36942 49256 55413 73884 110826 147768 221652 443304 27543853 55087706 82631559 110175412 165263118 220350824 247894677 330526236 495789354 661052472 991578708 1294561091 1983157416 2589122182 3608244743 3883683273 5178244364 7216489486 7767366546 10356488728 10824734229 11651049819 14432978972 15534733092 21649468458 23302099638 28865957944 31069466184 32474202687 43298936916 46604199276 64948405374 86597873832 93208398552 129896810748 169587502921 259793621496 339175005842 508762508763 678350011684 1017525017526 1356700023368 1526287526289 2035050035052 3052575052578 4070100070104 6105150105156 12210300210312