Base | Representation |
---|---|
bin | 10001110001010101010… |
… | …000001001110100111111 |
3 | 11022202010121011000012102 |
4 | 101301111100021310333 |
5 | 130002004424304413 |
6 | 2333002331455315 |
7 | 154141333212533 |
oct | 21612520116477 |
9 | 4282117130172 |
10 | 1221201009983 |
11 | 4309aa151749 |
12 | 1788158b753b |
13 | 8b20aa4b726 |
14 | 4316c123bc3 |
15 | 21b760e1458 |
hex | 11c55409d3f |
1221201009983 has 2 divisors, whose sum is σ = 1221201009984. Its totient is φ = 1221201009982.
The previous prime is 1221201009979. The next prime is 1221201010021. The reversal of 1221201009983 is 3899001021221.
It is an a-pointer prime, because the next prime (1221201010021) can be obtained adding 1221201009983 to its sum of digits (38).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1221201009983 - 22 = 1221201009979 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1221201009943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610600504991 + 610600504992.
It is an arithmetic number, because the mean of its divisors is an integer number (610600504992).
Almost surely, 21221201009983 is an apocalyptic number.
1221201009983 is a deficient number, since it is larger than the sum of its proper divisors (1).
1221201009983 is an equidigital number, since it uses as much as digits as its factorization.
1221201009983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 38.
The spelling of 1221201009983 in words is "one trillion, two hundred twenty-one billion, two hundred one million, nine thousand, nine hundred eighty-three".
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