Base | Representation |
---|---|
bin | 1011000110111001000101… |
… | …1111100110101111100000 |
3 | 1121020112222021020222201201 |
4 | 2301232101133212233200 |
5 | 3100044242422112000 |
6 | 41550331230410544 |
7 | 2400235225453513 |
oct | 261562137465740 |
9 | 47215867228651 |
10 | 12213033004000 |
11 | 3989577812894 |
12 | 1452b74060a54 |
13 | 6a78b7b97b3a |
14 | 30318497ad7a |
15 | 162a5066596a |
hex | b1b917e6be0 |
12213033004000 has 48 divisors (see below), whose sum is σ = 30007422100656. Its totient is φ = 4885213200000.
The previous prime is 12213033003979. The next prime is 12213033004001. The reversal of 12213033004000 is 40033031221.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12213033004001) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1526625126 + ... + 1526633125.
It is an arithmetic number, because the mean of its divisors is an integer number (625154627097).
Almost surely, 212213033004000 is an apocalyptic number.
12213033004000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12213033004000 is an abundant number, since it is smaller than the sum of its proper divisors (17794389096656).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12213033004000 is an equidigital number, since it uses as much as digits as its factorization.
12213033004000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3053258276 (or 3053258258 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 12213033004000 its reverse (40033031221), we get a palindrome (12253066035221).
The spelling of 12213033004000 in words is "twelve trillion, two hundred thirteen billion, thirty-three million, four thousand".
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