122131040131157 has 2 divisors, whose sum is σ = 122131040131158. Its totient is φ = 122131040131156.

The previous prime is 122131040131099. The next prime is 122131040131159. The reversal of 122131040131157 is 751131040131221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 96081438868996 + 26049601262161 = 9802114^2 + 5103881^2 .

It is a cyclic number.

It is not a de Polignac number, because 122131040131157 - 2⁸ = 122131040130901 is a prime.

Together with 122131040131159, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (122131040131159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61065520065578 + 61065520065579.

It is an arithmetic number, because the mean of its divisors is an integer number (61065520065579).

Almost surely, 2^{122131040131157} is an apocalyptic number.

It is an amenable number.

122131040131157 is a deficient number, since it is larger than the sum of its proper divisors (1).

122131040131157 is an equidigital number, since it uses as much as digits as its factorization.

122131040131157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5040, while the sum is 32.

Adding to 122131040131157 its reverse (751131040131221), we get a palindrome (873262080262378).

The spelling of 122131040131157 in words is "one hundred twenty-two trillion, one hundred thirty-one billion, forty million, one hundred thirty-one thousand, one hundred fifty-seven".