Base | Representation |
---|---|
bin | 11011110001001111101001… |
… | …011110101111000001010000 |
3 | 121000102122021010201022020201 |
4 | 123301033221132233001100 |
5 | 112001444411411210000 |
6 | 1111430203354144544 |
7 | 34503460525102552 |
oct | 3361175136570120 |
9 | 530378233638221 |
10 | 122131312210000 |
11 | 35a076648709a5 |
12 | 11845a49422154 |
13 | 531bc19687292 |
14 | 22232893a74d2 |
15 | e1bdb079996a |
hex | 6f13e97af050 |
122131312210000 has 100 divisors (see below), whose sum is σ = 295724865925984. Its totient is φ = 48847114800000.
The previous prime is 122131312209983. The next prime is 122131312210001. The reversal of 122131312210000 is 12213131221.
It is a tau number, because it is divible by the number of its divisors (100).
It is a self number, because there is not a number n which added to its sum of digits gives 122131312210000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (122131312210001) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 90238285 + ... + 91581715.
Almost surely, 2122131312210000 is an apocalyptic number.
122131312210000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 122131312210000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (147862432962992).
122131312210000 is an abundant number, since it is smaller than the sum of its proper divisors (173593553715984).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
122131312210000 is an equidigital number, since it uses as much as digits as its factorization.
122131312210000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1352550 (or 1352529 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 122131312210000 its reverse (12213131221), we get a palindrome (122143525341221).
122131312210000 divided by its reverse (12213131221) gives a 4-th power (10000 = 104).
The spelling of 122131312210000 in words is "one hundred twenty-two trillion, one hundred thirty-one billion, three hundred twelve million, two hundred ten thousand".
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