Base | Representation |
---|---|
bin | 1011000111010111100001… |
… | …1010100111010111101111 |
3 | 1121021100001121001010222021 |
4 | 2301311320122213113233 |
5 | 3100213010230400142 |
6 | 41554202012531011 |
7 | 2400644532463561 |
oct | 261657032472757 |
9 | 47240047033867 |
10 | 12221202200047 |
11 | 3991a8a043785 |
12 | 1454673a80a67 |
13 | 6a85ba49b359 |
14 | 30371b8c9331 |
15 | 162d7c933267 |
hex | b1d786a75ef |
12221202200047 has 2 divisors, whose sum is σ = 12221202200048. Its totient is φ = 12221202200046.
The previous prime is 12221202199979. The next prime is 12221202200057. The reversal of 12221202200047 is 74000220212221.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12221202200047 - 211 = 12221202197999 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12221202199994 and 12221202200030.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12221202200057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6110601100023 + 6110601100024.
It is an arithmetic number, because the mean of its divisors is an integer number (6110601100024).
Almost surely, 212221202200047 is an apocalyptic number.
12221202200047 is a deficient number, since it is larger than the sum of its proper divisors (1).
12221202200047 is an equidigital number, since it uses as much as digits as its factorization.
12221202200047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1792, while the sum is 25.
Adding to 12221202200047 its reverse (74000220212221), we get a palindrome (86221422412268).
The spelling of 12221202200047 in words is "twelve trillion, two hundred twenty-one billion, two hundred two million, two hundred thousand, forty-seven".
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