Base | Representation |
---|---|
bin | 1011001000000011100011… |
… | …1000101011111101000111 |
3 | 1121022110120021122202012112 |
4 | 2302000320320223331013 |
5 | 3100411211414240312 |
6 | 42003434500011235 |
7 | 2401543445625422 |
oct | 262007070537507 |
9 | 47273507582175 |
10 | 12233021243207 |
11 | 3996aa4639846 |
12 | 1456a12090b1b |
13 | 6a9751cb560b |
14 | 30411d4809b9 |
15 | 16332035bd22 |
hex | b2038e2bf47 |
12233021243207 has 2 divisors, whose sum is σ = 12233021243208. Its totient is φ = 12233021243206.
The previous prime is 12233021243189. The next prime is 12233021243243. The reversal of 12233021243207 is 70234212033221.
12233021243207 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (70234212033221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12233021243207 - 26 = 12233021243143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12233021242207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6116510621603 + 6116510621604.
It is an arithmetic number, because the mean of its divisors is an integer number (6116510621604).
Almost surely, 212233021243207 is an apocalyptic number.
12233021243207 is a deficient number, since it is larger than the sum of its proper divisors (1).
12233021243207 is an equidigital number, since it uses as much as digits as its factorization.
12233021243207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24192, while the sum is 32.
Adding to 12233021243207 its reverse (70234212033221), we get a palindrome (82467233276428).
The spelling of 12233021243207 in words is "twelve trillion, two hundred thirty-three billion, twenty-one million, two hundred forty-three thousand, two hundred seven".
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