Base | Representation |
---|---|
bin | 10001110101001100001… |
… | …010001000100110100111 |
3 | 11100010211021210110010220 |
4 | 101311030022020212213 |
5 | 130034000402420310 |
6 | 2334525345415423 |
7 | 154346103041412 |
oct | 21651412104647 |
9 | 4303737713126 |
10 | 1225343404455 |
11 | 432735452a55 |
12 | 17959103a573 |
13 | 8b71b008311 |
14 | 43442342b79 |
15 | 21d19ae2670 |
hex | 11d4c2889a7 |
1225343404455 has 64 divisors (see below), whose sum is σ = 2015945625600. Its totient is φ = 635252834304.
The previous prime is 1225343404429. The next prime is 1225343404457. The reversal of 1225343404455 is 5544043435221.
It is not a de Polignac number, because 1225343404455 - 26 = 1225343404391 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1225343404457) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 80942647 + ... + 80957783.
It is an arithmetic number, because the mean of its divisors is an integer number (31499150400).
Almost surely, 21225343404455 is an apocalyptic number.
1225343404455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1225343404455 is a deficient number, since it is larger than the sum of its proper divisors (790602221145).
1225343404455 is a wasteful number, since it uses less digits than its factorization.
1225343404455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15968.
The product of its (nonzero) digits is 1152000, while the sum is 42.
Adding to 1225343404455 its reverse (5544043435221), we get a palindrome (6769386839676).
The spelling of 1225343404455 in words is "one trillion, two hundred twenty-five billion, three hundred forty-three million, four hundred four thousand, four hundred fifty-five".
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