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122564113117 is a prime number
BaseRepresentation
bin111001000100101100…
…0111111001011011101
3102201100201000001102221
41302021120333023131
54002002403104432
6132145530145341
711566152525565
oct1621130771335
9381321001387
10122564113117
1147a85279276
121b906582251
13b7334a3974
145d09ac5da5
1532c5147b97
hex1c8963f2dd

122564113117 has 2 divisors, whose sum is σ = 122564113118. Its totient is φ = 122564113116.

The previous prime is 122564113103. The next prime is 122564113151. The reversal of 122564113117 is 711311465221.

It is an a-pointer prime, because the next prime (122564113151) can be obtained adding 122564113117 to its sum of digits (34).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 121955306841 + 608806276 = 349221^2 + 24674^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-122564113117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (122564113817) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61282056558 + 61282056559.

It is an arithmetic number, because the mean of its divisors is an integer number (61282056559).

Almost surely, 2122564113117 is an apocalyptic number.

It is an amenable number.

122564113117 is a deficient number, since it is larger than the sum of its proper divisors (1).

122564113117 is an equidigital number, since it uses as much as digits as its factorization.

122564113117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10080, while the sum is 34.

Adding to 122564113117 its reverse (711311465221), we get a palindrome (833875578338).

The spelling of 122564113117 in words is "one hundred twenty-two billion, five hundred sixty-four million, one hundred thirteen thousand, one hundred seventeen".