Base | Representation |
---|---|
bin | 1011001011001100110110… |
… | …0111010111000010111010 |
3 | 1121111122001001210120210211 |
4 | 2302303031213113002322 |
5 | 3102302342331120400 |
6 | 42044332354501334 |
7 | 2405465463510430 |
oct | 262631547270272 |
9 | 47448031716724 |
10 | 12287056113850 |
11 | 3a07a02942931 |
12 | 146539229484a |
13 | 6b188396595b |
14 | 3069a7a00d50 |
15 | 164934063dba |
hex | b2ccd9d70ba |
12287056113850 has 96 divisors (see below), whose sum is σ = 26321390323200. Its totient is φ = 4180058308800.
The previous prime is 12287056113811. The next prime is 12287056113877. The reversal of 12287056113850 is 5831165078221.
It is a junction number, because it is equal to n+sod(n) for n = 12287056113794 and 12287056113803.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 88035421 + ... + 88174879.
It is an arithmetic number, because the mean of its divisors is an integer number (274181149200).
Almost surely, 212287056113850 is an apocalyptic number.
12287056113850 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12287056113850 is an abundant number, since it is smaller than the sum of its proper divisors (14034334209350).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12287056113850 is a wasteful number, since it uses less digits than its factorization.
12287056113850 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 141428 (or 141423 counting only the distinct ones).
The product of its (nonzero) digits is 806400, while the sum is 49.
The spelling of 12287056113850 in words is "twelve trillion, two hundred eighty-seven billion, fifty-six million, one hundred thirteen thousand, eight hundred fifty".
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