12301131343500 has 144 divisors (see below), whose sum is σ = 40057774917888. Its totient is φ = 3174485472000.

The previous prime is 12301131343451. The next prime is 12301131343519. The reversal of 12301131343500 is 534313110321.

12301131343500 is a `hidden beast` number, since 1 + 2 + 3 + 0 + 113 + 1 + 3 + 43 + 500 = 666.

It is a super-2 number, since 2×12301131343500² (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 43950577 + ... + 44229576.

Almost surely, 2^{12301131343500} is an apocalyptic number.

12301131343500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

12301131343500 is an abundant number, since it is smaller than the sum of its proper divisors (27756643574388).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12301131343500 is a wasteful number, since it uses less digits than its factorization.

12301131343500 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 88180209 (or 88180194 counting only the distinct ones).

The product of its (nonzero) digits is 3240, while the sum is 27.

Adding to 12301131343500 its reverse (534313110321), we get a palindrome (12835444453821).

The spelling of 12301131343500 in words is "twelve trillion, three hundred one billion, one hundred thirty-one million, three hundred forty-three thousand, five hundred".