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123011321971061 is a prime number
BaseRepresentation
bin11011111110000011001110…
…001001100100000101110101
3121010112202201112100000220002
4123332003032021210011311
5112110404141411033221
61113342342101321045
734624163142462236
oct3376031611440565
9533482645300802
10123011321971061
1136216899399367
1211968502a06185
135383bc17a5624
142253acb8c908d
15e34c17d3780b
hex6fe0ce264175

123011321971061 has 2 divisors, whose sum is σ = 123011321971062. Its totient is φ = 123011321971060.

The previous prime is 123011321971019. The next prime is 123011321971063. The reversal of 123011321971061 is 160179123110321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 122818924816900 + 192397154161 = 11082370^2 + 438631^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-123011321971061 is a prime.

It is a super-2 number, since 2×1230113219710612 (a number of 29 digits) contains 22 as substring.

Together with 123011321971063, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123011321971063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61505660985530 + 61505660985531.

It is an arithmetic number, because the mean of its divisors is an integer number (61505660985531).

Almost surely, 2123011321971061 is an apocalyptic number.

It is an amenable number.

123011321971061 is a deficient number, since it is larger than the sum of its proper divisors (1).

123011321971061 is an equidigital number, since it uses as much as digits as its factorization.

123011321971061 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13608, while the sum is 38.

The spelling of 123011321971061 in words is "one hundred twenty-three trillion, eleven billion, three hundred twenty-one million, nine hundred seventy-one thousand, sixty-one".