Base | Representation |
---|---|
bin | 1011001100000001111101… |
… | …0101010100111000110101 |
3 | 1121112222211120210122122200 |
4 | 2303000133111110320311 |
5 | 3103021041334120041 |
6 | 42055051132215113 |
7 | 2406511656640203 |
oct | 263003725247065 |
9 | 47488746718580 |
10 | 12301312020021 |
11 | 3a12a58a39172 |
12 | 14680b060a499 |
13 | 6b30162a45ab |
14 | 30755b090073 |
15 | 164eba8961b6 |
hex | b301f554e35 |
12301312020021 has 96 divisors (see below), whose sum is σ = 19688616604800. Its totient is φ = 7368759889920.
The previous prime is 12301312019977. The next prime is 12301312020031. The reversal of 12301312020021 is 12002021310321.
12301312020021 is a `hidden beast` number, since 12 + 301 + 312 + 0 + 20 + 0 + 21 = 666.
12301312020021 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12301312020021 - 26 = 12301312019957 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12301312019976 and 12301312020003.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12301312020031) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 65908410 + ... + 66094788.
It is an arithmetic number, because the mean of its divisors is an integer number (205089756300).
Almost surely, 212301312020021 is an apocalyptic number.
It is an amenable number.
12301312020021 is a deficient number, since it is larger than the sum of its proper divisors (7387304584779).
12301312020021 is a wasteful number, since it uses less digits than its factorization.
12301312020021 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 186659 (or 186656 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 12301312020021 its reverse (12002021310321), we get a palindrome (24303333330342).
It can be divided in two parts, 123013120 and 20021, that added together give a triangular number (123033141 = T15686).
The spelling of 12301312020021 in words is "twelve trillion, three hundred one billion, three hundred twelve million, twenty thousand, twenty-one".
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